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support first_word with no found second_word

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useful for "!markov <word>" so that "<word>" can be mid-chain
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jesopo 2019-09-23 16:47:11 +01:00
parent 7656fb9b51
commit 6669926746
1 changed files with 13 additions and 3 deletions
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12
modules/markov.py
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@ -126,10 +126,20 @@ class Module(ModuleManager.BaseModule):
frequency FROM markov WHERE channel_id=? AND first_word IS NULL AND frequency FROM markov WHERE channel_id=? AND first_word IS NULL AND
second_word=? AND third_word NOT NULL""", [channel_id, first_word]) second_word=? AND third_word NOT NULL""", [channel_id, first_word])
if not second_words: if not second_words:
second_two_words = self.bot.database.execute_fetchall("""SELECT
second_word, third_word, frequency FROM markov WHERE
channel_id=? AND first_word=? AND second_word NOT NULL AND
third_word NOT NULL""", [channel_id, first_word])
if not second_two_words:
return None return None
second_word = self._choose(second_words)
second_word, third_word = self._choose(
[[[s, t], f] for s, t, f in second_two_words])
words = [first_word, second_word, third_word]
else:
second_word = self._choose(second_words)
words = [first_word, second_word] words = [first_word, second_word]
for i in range(30): for i in range(30):
two_words = words[-2:] two_words = words[-2:]
third_words = self.bot.database.execute_fetchall("""SELECT third_words = self.bot.database.execute_fetchall("""SELECT